题目描述：

Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

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Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
    The maximum number of consecutive 1s is 3.

Note:

  • The input array will only contain 0 and 1.
  • The length of input array is a positive integer and will not exceed 10,000

最长的连续1的个数。很简单，方法也很多。一开始在最后加一个0是为了方便结尾的处理。

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class Solution {
public:
    int findMaxConsecutiveOnes(vector<int>& nums) {
        nums.push_back(0);
        int maxNum = 0;
        int beginIndex = -1;
        for (int i = 0; i < nums.size(); i++) {
            if(nums[i] == 1 && beginIndex == -1){
                beginIndex = i;
            }
            else if(nums[i] == 0){
                if(beginIndex != -1){
                    maxNum = max(maxNum, i - beginIndex);
                }
                beginIndex = -1;
            }
        }
        return maxNum;
    }
};