LeetCode 58. Length of Last Word

题目描述:

Given a string s consists of upper/lower-case alphabets and empty space characters ’ ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, Given s = “Hello World”, return 5.

找出一个字符串中最后一个单词的长度, 没有什么好说的, 从后往前搜索.

class Solution {
public:
    int lengthOfLastWord(string s) {
        int end = s.size();
        if(end == 0)
            return 0;
        for(; end >= 1 && s[end - 1] == ' '; end--); // 跳过结尾的空格
        int i;
        for(i = end - 1; i >= 0 && s[i] != ' '; i--);
        return end - i - 1;
    }
};