题目描述:

Find the contiguous subarray within an array (containing at least one number) which has the largest product.

For example, given the array [2,3,-2,4], the contiguous subarray [2,3] has the largest product = 6.

DP问题, 主要问题在于数组中可能会出现负数, 所以要在维护最大值的同时维护一个最小值, 因为如果一个元素为负, 那么最小值也有可能变为最大值.

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class Solution {
public:
    int maxProduct(vector<int>& nums) {
        int maxPrevP = nums[0], minPrevP = nums[0], maxP = nums[0];
        for(int i = 1; i < nums.size(); i++){
            int maxCurP = max(maxPrevP * nums[i], max(nums[i], minPrevP * nums[i]));
            int minCurP = min(maxPrevP * nums[i], min(nums[i], minPrevP * nums[i]));
            if(maxP < maxCurP) maxP = maxCurP;
            maxPrevP = maxCurP, minPrevP = minCurP;
        }
        return maxP;
    }
};