题目描述:

Given an index k, return the kth row of the Pascal’s triangle.

For example, given k = 3, Return [1,3,3,1].

Note: Could you optimize your algorithm to use only O(k) extra space?

与上一题类似, 只不过现在是要求某一行的结果. 每计算一行只需要上一行的数据, 所以只需要保存一行.

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class Solution {
public:
    vector<int> getRow(int rowIndex) {
        vector<int> ret = {1};
        vector<int> last = {1};
        for(int i = 1; i <= rowIndex; i++){
            ret.clear();
            ret.push_back(last[0]);
            auto j = last.begin() + 1;
            for(; j != last.end(); j++){
                ret.push_back(*j + *(j - 1));
            }
            ret.push_back(*(j - 1));
            last = ret;
        }
        
        return ret;
    }
};